A distance-time graph shows how the?distance?of an object moving in a straight line (from a starting position) varies over time:
This graph shows a moving object moving further away from its origin
Constant Speed on a Distance-Time Graph
Distance-time graphs also show the following information:
If the object is moving at a?constant speed
How?large?or?small?the speed is
A?straight line?represents?constant speed
The slope of the straight line represents the?magnitude?of the speed:
A very?steep?slope means the object is moving at a?large?speed
A?shallow?slope means the object is moving at a?small?speed
A?flat,?horizontal?line?means the object is?stationary?(not moving)
This graph shows how the slope of a line is used to interpret the speed of moving objects. Both of these objects are moving with a constant speed, because the lines are straight.
Changing Speed on a Distance-Time Graph
Objects might be moving at a?changing speed
This is represented by a?curve
In this case, the slope of the line will be changing
If the slope is?increasing, the?speed?is?increasing?(accelerating)
If the slope is?decreasing, the?speed?is?decreasing?(decelerating)
The image below shows two different objects moving with changing speeds
Changing speeds are represented by changing slopes. The red line represents an object slowing down and the green line represents an object speeding up.
Gradient of a Distance-Time Graph
The?speed?of a moving object can be calculated from the?gradient?of the line on a?distance-time?graph:
The speed of an object can be found by calculating the gradient of a distance-time graph
The?rise?is the?change?in y (distance) values
The?run?is the?change?in x (time) values
Worked Example
A distance-time graph is drawn below for part of a train journey. The train is travelling at a constant speed.Calculate the speed of the train.
Step 1: Draw a large gradient triangle on the graph and label the magnitude of the rise and run
The image below shows a large?gradient triangle?drawn with dashed lines
The?rise?and?run?magnitude is labelled, using the?units?as stated on each axes
Step 2: Convert units for distance and time into standard units
The distance travelled (rise) = 8 km =?8000 m
The time taken (run) = 6 mins =?360 s
Step 3: State that speed is equal to the gradient of a distance-time graph
The?gradient?of a?distance-time?graph is equal to the?speed?of a moving object:
Step 4: Substitute values in to calculate the speed
speed = gradient = 8000 ÷ 360
speed =?22.2 m/s
Worked Example
Ose decides to take a stroll to the park. He finds a bench in a quiet spot and takes a seat, picking up where he left off reading his book on Black Holes.After some time reading, Ose realises he lost track of time and runs home.A distance-time graph for his trip is drawn below:a) How long does Ose spend reading his book?There are three sections labelled on the graph: A, B and C.b) Which section represents Ose running home?
c) What is the total distance travelled by Ose?
Part (a)
Ose spends?40 minutes?reading his book
The?flat?section of the line (section B) represents an object which is?stationary?- so section B represents Ose sitting on the bench reading
This section lasts for?40 minutes?- as shown in the graph below
Part (b)
Section C?represents Ose running home
The?slope?of the line in section C is?steeper?than the slope in section A
This means Ose was moving with a?larger?speed (running) in section C
Part (c)
The total distance travelled by Ose is?0.6 km
The total?distance?travelled by an object is given by the final point on the line - in this case, the line ends at?0.6 km?on the?distance?axis. This is shown in the image below:
Exam Tip
Use the?entire line, where possible, to calculate the gradient. Examiners tend to award credit if they see a?large gradient triangle?used - so remember to draw these directly on the graph itself!
Remember to check the?units?of variables measured on each axis. These may not always be in standard units - in our example, the unit of distance was?km?and the unit of time was?minutes. Double-check which units to use in your answer.