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千千萬萬遍
共計3小時考試時間
此套試卷由25道選擇題以及3道大題組成
每道大題含有不同數量的小題
Part A選擇題部分:
Part B簡答題部分
Solution to Problem 1:
The internal resistance of the capacitor is small compared with the dynamic resistance of the diode at the operating current, so it can be ignored.
Q(t)/C+ R(t)I + VLED =0
I = I0 is to be kept constant at 800 mA, so
Q(t)= Q0 ? I0 t
... where Q0 is the initial charge.
Q0 = V0 C (Q0 ? I0 t)/C? R(t)I0 ? VLED =0 V0 ? I0 t/C ? R(t)I0 ? VLED =0 V0 /I0 ? t/C ? R(t)? VLED/I0 =0 R(t)= ?t/C ? VLED/I0 + V0 /I0
Therefore R0 has to be R0 =(V0 ? VLED)/I0 =(5? 2.7)/0.5=2.9Ω
R(t)= ?t/C + R0 = R0 ? t/C
R(t)cannot be negative, so tmax = R0 C =3000× 2.9 =8600 s,thatis2.4hours.
完整版真題資料可以底部二維碼免費領取↓↓↓
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