The apparent change in wavelength or frequency of the radiation from a source due to its relative motion away from or toward the observer
The fractional increase in wavelength (or decrease in frequency) due to the source and observer receding from each other

The spectra below show dark absorption lines against a continuous visible spectrum.
A particle line in the spectrum of light from a source in the laboratory has a frequency of 4.570 × 1014?Hz. The same line in the spectrum of light from a distant galaxy has a frequency of 4.547 × 1014 Hz. What speed is the distance galaxy moving in relation to the Earth? Is it moving towards or away from the Earth?
Step 1:??????????? Write down the known quantities
Emitted frequency, f =?4.570 × 1014?Hz
Shift in frequency, Δf?= (4.547 – 4.570) × 1014?= –2.3 × 1012?Hz
Speed of light, c =?3.0 × 108?m s–1
Step 2:??????????? Write down the Doppler redshift equation

Step 3:??????????? Rearrange for speed v, and calculate

Step 4: ???????????Write a concluding sentence
The observed frequency is?less?than the emitted frequency (the light from a laboratory source), therefore, the source is?receding, or moving away, from the Earth at?1.5 × 106?m s–1
In your exam, be sure to emphasise that redshift means the wavelength of spectral lines increases towards the red end of the spectrum,?do not?say that the spectral lines become red, as this is incorrect.

A balloon inflating is similar to the stretching of the space between galaxies
轉載自savemyexams
以上就是關于【CIE A Level Physics復習筆記25.2.2 Doppler Redshift】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
往期文章閱讀推薦:
2026 ALEVEL 夏考A率出爐!愛德思vs牛津AQA,哪些科目真的“好出分”?
2026 AMC10/12美國數學競賽新賽季!【翰林教育 × 清華大學出版社】獨家教材全面發售!

? 2026. All Rights Reserved. 滬ICP備2023009024號-1