The total power output of radiation emitted by a star
It is measured in units of?Watts (W)
Radiant flux intensity?F?is defined as:
The observed amount of intensity, or the radiant power transmitted normally through a surface per unit of area, of radiation measured on Earth
The best way to picture this is:
The luminosity is the total radiation that?leaves?the star
The radiant flux intensity is the amount of radiation?measured on Earth
By the time the radiation reaches the Earth, it will have spread out a great deal, therefore, it will only be a fraction of the value of the luminosity
The luminosity is the total power output of the star, whereas the radiant flux is what is measured on Earth
Inverse Square Law of Flux
Light sources which are further away appear fainter because the light it emits is spread out over a greater area
The moment the light leaves the surface of the star, it begins to spread out uniformly through a spherical shell
The surface area of a sphere is equal to?4πr2
The radius?r?of this sphere is equal to the distance?d?between the star and the Earth
By the time the radiation reaches the Earth, it has been spread over an area of 4πd2
The inverse square law of flux can therefore be calculated using:
Where:
F?= radiant flux intensity, or observed intensity on Earth (W m-2)
L?= luminosity of the source (W)
d?= distance between the star and the Earth (m)
This equation assumes:
The power from the star radiates uniformly through space
No radiation is absorbed between the star and the Earth
This equation tells us:
For a given star, the luminosity is constant
The radiant flux follows an inverse square law
The greater the radiant flux (larger?F) measured, the closer the star is to the Earth (smaller?d)
Inverse square law; when the light is twice as far away, it has spread over four times the area, hence the intensity is four times smaller
Worked Example
A star has a luminosity that is known to be 4.8 × 1029?W. A scientist observing this star finds that the radiant flux intensity of light received on Earth from the star is 2.6?nW?m–2Determine the distance of the star from Earth.