Chemists routinely prepare solutions needed for analysis, whose concentrations are known precisely
These solutions are termed?standard solutions
They are made as accurately and precisely as possible using three decimal place balances and volumetric flasks to reduce the impact of measurement uncertainties
The steps are:
Volumes & concentrations of solutions
The?concentration?of a solution is the amount of?solute?dissolved in a?solvent?to make 1 dm3?of??solution
The solute is the substance that dissolves in a solvent to form a solution
The solvent is often water
A?concentrated?solution is a solution that has a?high?concentration of solute
A?dilute?solution is a solution with a?low?concentration of solute
Concentration is usually expressed in one of three ways:
moles per unit volume
mass per unit volume
parts per million
Moles per unit volume
The formula for expressing concentration using moles is:
You must make sure you change cm3?to dm3??(by dividing by 1000)
The relationships can be expressed using this formula triangle:
To use the concentration formula triangle cover the one you want to find out about with your finger and follow the instructions
Worked Example
Calculate the mass of sodium hydroxide, NaOH, required to prepare 250 cm3?of a 0.200 mol dm-3 solution
Answer:
Step 1: Use the formula triangle to find the number of moles of NaOH needed
number of moles? =?concentration (mol dm-3)?x?volume (dm3)??
n = 0.200?mol dm-3?x 0.250?dm3
n =?0.0500 mol
Step 2:?Find the molar mass of NaOH
M?= 22.99 + 16.00 + 1.01 = 40.00 g mol-1
Step 3: Calculate the mass required
mass = moles x molar mass
mass =? 0.0500 mol x 40.00 g mol-1?? =?2.00 g
Mass per unit volume
Sometimes it is more convenient to express concentration in terms of mass per unit volume
The formula is:
To change a concentration from mol dm-3?to g dm-3
Multiply the moles of solute by its molar mass
mass of solute (g) = number of moles (mol) x molar mass (g mol-1)
Parts per million
When expressing extremely low concentrations a unit that can be used is?parts per million?or?ppm
This is useful when giving the concentration of a pollutant in water or the air when the absolute amount is tiny compared the the volume of water or air
1 ppm?is defined as
A mass of?1 mg?dissolved in?1 dm3?of water
Since 1 dm3?weighs 1 kg we can also say it is
A mass of?1 mg?dissolved in?1 kg?of water, or 10-3?g in 103?g which is the same as saying the concentration is?1 in?106?or?1 in a million
Worked Example
The concentration of chlorine in a swimming pool should between between 1 and 3 ppm. Calculate the maximum mass, in kg, of chlorine that should be present in an olympic swimming pool of size 2.5 million litres.
Answer:
Step 1: calculate the total mass in mg assuming 3ppm(1 litre is the same as 1 dm3)
3 x 2.5 x 106?= 7.5 x 106?mg
Step 2: convert the mass into kilograms (1 mg = 10-6?kg)
7.5 x 106??x 10-6??kg =?7.5 kg
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