Core Practical 11: Investigating Specific Heat Capacity
Aim of the Experiment
The aim of this experiment is to determine the specific heat capacity of a solid and of water by measuring the energy required to increase the temperature of a known amount by one degree
Equipment List
Resolution?of measuring equipment:
Thermometer = 0.1 °C
Voltmeter = 0.1 V
Ammeter = 0.1 A
Stopwatch = 0.01 s
Digital balance = 0.1 g
Method
Apparatus for heating water and measuring energy supplied
Place the beaker on the digital balance and press 'tare'
Add approximately 250 ml of water and record the mass of the water using the digital balance
Place the immersion heater and thermometer in the water
Connect up the circuit as shown in the diagram, with the ammeter in series with the power supply and immersion heater, and the voltmeter in parallel with the immersion heater
Record the initial temperature of the water at time 0 s
Turn on the power supply, set it at approximately 10 V, and start the stopwatch
Record the voltage from the voltmeter and the current from the ammeter
Continue to record the temperature, voltage and current every 60 seconds for 10 minutes
Repeat steps 2-8, replacing the beaker of water for the solid block of aluminium and starting with recording its mass using the digital balance
An example of a results table might look like this:
Analysis of Results
Calculate the energy supplied every 60 seconds using the formula:
Electrical energy = voltage × current × time
Where:
Electrical energy is measured in Joules (J)
Voltage is measured in volts (V)
Current is measured in amps (A)
Time is measured in seconds (s)
Calculate the temperature change by subtracting the temperature at time 0 s from the temperature recorded each minute
The equation for specific heat capacity is:
ΔQ?=?m?×?c?× ΔT
Where:
ΔQ?= change in thermal energy, in joules (J)
m?= mass of substance, in kilograms (kg)
c?= specific heat capacity, in joules per kilogram per degree Celsius (J/kg °C)
ΔT?= change in temperature, in degrees Celsius (°C)
Plot a graph of the energy supplied (y-axis) against the temperature change multiplied by the average mass (x-axis)
Calculate the gradient of this graph in the straight line region in order to obtain the specific heat capacity of the water or solid block
The gradient of the graph is equal to the specific heat capacity of the substance, assuming a perfectly efficient immersion heater
Evaluating the Experiment
Systematic Errors:
Ensure the digital balance is set to zero before taking measurements of mass
Some water may be lost to the surroundings by evaporation. Calculate an average mass of water (using the mass before the experiment and the mass after) to account for this
Remember to only take gradients on the straight-line region
Before this point the energy supplied is being used to heat the immersion heater itself
Random Errors:
Stir the water constantly whilst heating it to ensure the temperature measured is the temperature throughout the fluid
When the current or voltage values appear to be changing between two values next to one another then be consistent in choosing the higher value
Safety Considerations
The immersion heater will get very?hot
Make sure not to touch it, and have a heatproof mat ready to place it on
Make sure that the immersion heater is connected to a?Direct Current?supply
The beaker may become?unstable?with an immersion heater and thermometer resting in it
If you feel this is the case then use a clamp stand to hold both
Wear goggles while heating water
Make sure to stand up during the whole experiment, to react quickly to any spills
Exam Tip
Although there is a lot of detail here, if you can begin any questions about this experiment by writing down the equation for specific heat capacity then you will have given yourself some clues about how best to proceedTaking a gradient is a more reliable way of determining an answer than just using a single value, so take time to understand the process of plotting graphs and using their gradients to make conclusions