
Path difference of constructive and destructive interference is determined by wavelength

Interference pattern of light waves shown with orders of maxima

Young’s double-slit experiment arrangement
Two coherent sources of sound waves S1?and S2?are situated 65 cm apart in air as shown below.
The two sources vibrate in phase but have different amplitudes of vibration. A microphone M is situated 150 cm from S1 along the line normal to S1?and S2. The microphone detects maxima and minima of the intensity of the sound. The wavelength of the sound from S1?to S2?is decreased by increasing the frequency.Determine which orders of maxima are detected at M as the wavelength is increased from 3.5 cm to 12.5 cm.

The path difference is more specifically how much longer, or shorter, one path is than the other. In other words, the?difference?in the distances. Make sure not to confuse this with the distance between the two paths.

Double slit interference equation with w, s and D represented on a diagram
A laser is placed in front of a double-slit as shown in the diagram below.
The laser emits light of frequency 750 THz. The separation of the maxima P and Q observed on the screen is 15 mm. The distance between the double slit and the screen is 4.5 m.Calculate the separation of the two slits.

Since?w,?s?and?D?are all distances, it's easy to mix up which they refer to. Labelling the double-slit diagram as shown in the notes above will help to remember the order i.e.?w?and?s?in the numerator and?D?underneath in the denominator.

Each fringe appears as a visible spectrum apart from the central white fringe. Red is diffracted the most, violet is diffracted the least
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