• In a lot of reactions, not all reactants react to form products which can be due to several factors:
  • Other reactions take place simultaneously
  • The reaction does not go to?completion
  • Reactants or products are?lost?to the atmosphere

   

• The?percentage yield?shows how much of a particular product you get from the reactants compared to the maximum theoretical amount that you can get:

• The?actual yield?is the number of moles or mass of product obtained?experimentally
• The?predicted yield?is the number of moles or mass obtained by calculation

• You will often have to use the following equation to work out the reacting masses, to calculate the predicted yield

• It is important to be clear about the type of particle you are referring to when dealing with moles
  • Eg. 1 mole of CaF2?contains one mole of CaF2?formula units, but one mole of Ca2+?and two moles of F-?ions

   

Answer

Step 1:?The symbol equation is:

Zn (s) ???+ ???CuSO4?(aq) ????→ ????ZnSO4?(aq) ???+ Cu (s)

Step 2:?Calculate the amount of zinc reacted in moles

Step 3:?Calculate the maximum amount of copper that could be formed from the molar ratio:

Since the ratio of Zn(s) to Cu(s) is 1:1 a maximum of 0.10 moles can be produced

Step 4:?Calculate the maximum mass of copper that could be formed (theoretical yield)

mass =?? mol?? x?? Mr

mass =?? 0.10 mol x 64 g mol-1

mass =?? 6.4 gStep 5:?Calculate the percentage yield of copper

Limiting & Excess reagents

• Sometimes, there is an?excess?of one or more of the reactants (excess reagent)
• The reactant which is not in excess is called the?limiting reagent
• To determine which reactant is limiting:
  • The number of moles of each reactant should be calculated
  • The ratio of the reactants shown in the equation should be taken into account e.g.

   

2Na + S → Na2S

• Here, the ratio of Na : S is 2 : 1, and this should be taken into account when doing calculations
• Once all of one reactant has been used up, the reaction will stop, even if there are moles of the other reactant(s) leftover
  • The reactant leftover is in excess, the reactant which causes the reaction to stop once it is used up is the limiting reagent

   

Answer

Step 1:?Calculate the moles of each reactant

Step 2:?Write the balanced equation and determine the molar ratio

2Na + S → Na2S

The molar ratio of Na: Na2S is 2:1

Step 3:?Compare the moles and determine the limiting reagent

So to react completely 0.40 moles of Na require 0.20 moles of S and since there are 0.25 moles of S, then S is in excess. Na is therefore the limiting reactant.

Once all of the S has been used up, the reaction will stop, even though there is Na left.