Phenotype frequency = (total individuals with phenotype ÷ total individuals in population) × 100
In a population of 9 pea plants, 7 of the plants have purple flowers, whilst 2 have white flowers. Calculate the phenotype frequencies of purple and white flowers. Give your answers as percentages.
Two phenotypes of pea plant flowers

Step 1: Calculate the phenotype frequency of purple flowers
Phenotype frequency = (total individuals with phenotype ÷ total individuals in population) × 100
= (7 ÷ 9) × 100
= 0.78 × 100
= 78%
Step 2: Calculate the phenotype frequency of white flowers
Phenotype frequency = (total individuals with phenotype ÷ total individuals in population) × 100
= (2 ÷ 9) × 100
= 0.22 × 100
= 22%
In banded snails (Cepaea nemoralis), shell colour is controlled by two alleles of a single gene. The pink allele (C?) is dominant over the yellow allele (C?). Out of a sample of individuals collected, 275 snails have the genotype C?C?, 150 have the genotype C?C?, and 75 have the genotype C?C?. Calculate the relative phenotype frequencies of the banded snails collected.
Two phenotypes of banded snails

Step 1: Calculate the total number of snails in the sample
= 275 + 150 + 75
= 500
Step 2: Calculate the total number of pink-shelled snails (genotypes: C?C? and C?C?)
= 275 + 150
425
Step 3: Calculate the phenotype frequency of pink-shelled snails
Phenotype frequency = (total individuals with phenotype ÷ total individuals in population) × 100
= (425 ÷ 500) × 100
= 0.85 × 100
= 85%
Step 4: Calculate the phenotype frequency of yellow-shelled snails
Phenotype frequency = (total individuals with phenotype ÷ total individuals in population) × 100
= (75 ÷ 500) × 100
= 0.15 × 100
= 15%
轉載自savemyexams
以上就是關于【AQA A Level Biology復習筆記7.2.2 Gene Pools & Allele Frequency】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
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